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Geometric Series: Formula, Examples and How to Find the Sum

A geometric series adds numbers that are multiplied by the same factor each time, such as 2+6+18+542 + 6 + 18 + 54. There is one formula to remember and one condition to check when the sum goes on forever. This article covers the formula, where it comes from, and the examples that appear most often in exams.

By Ajarn ModUpdated
30-second summary
  • General term: an=a1rn−1a_n = a_1 r^{n-1}, where rr is the common ratio =an+1/an= a_{n+1}/a_n
  • Sum of n terms: Sn=a11−rn1−rS_n = a_1\dfrac{1 - r^n}{1 - r} for r≠1r \ne 1
  • Infinite series: S∞=a11−rS_\infty = \dfrac{a_1}{1 - r}, valid only when ∣r∣<1|r| < 1

What is a geometric series?

A geometric sequence is a sequence in which each term is the previous one multiplied by a constant rr, for example 2,6,18,54,…2, 6, 18, 54, \dots with r=3r = 3. A geometric series is the sum of those terms, 2+6+18+54+⋯2 + 6 + 18 + 54 + \cdots.

To find rr, divide any term by the one before it. If every pair gives the same value, the sequence is geometric. rr can be negative (the signs alternate) or a fraction (the terms shrink).

Sum of n terms, and where the formula comes from

Sn=a1+a1r+a1r2+⋯+a1rn−1=a1 1−rn1−r,r≠1S_n = a_1 + a_1r + a_1r^2 + \cdots + a_1r^{n-1} = a_1\,\frac{1 - r^n}{1 - r},\quad r \ne 1

The derivation takes two lines: write SnS_n, then multiply by rr. You get the same terms shifted by one place.

Sn=a1+a1r+⋯+a1rn−1rSn=a1+a1r+⋯+a1rn−1+a1rn\begin{aligned} S_n &= a_1 + a_1r + \cdots + a_1r^{n-1} \\ rS_n &= \phantom{a_1 + {}} a_1r + \cdots + a_1r^{n-1} + a_1r^n \end{aligned}

Subtract: all the middle terms cancel, leaving Sn−rSn=a1−a1rnS_n - rS_n = a_1 - a_1r^n, which gives the formula above. When r>1r > 1 you can write it as a1rn−1r−1a_1\dfrac{r^n - 1}{r - 1} instead (same value, fewer minus signs).

Example 1

A geometric sequence has a2=6a_2 = 6 and a5=162a_5 = 162. Find S6S_6.

  1. a5a2=r3=1626=27\dfrac{a_5}{a_2} = r^3 = \dfrac{162}{6} = 27, so r=3r = 3 and a1=a2/r=2a_1 = a_2/r = 2

  2. S6=2⋅36−13−1=2⋅7282=728S_6 = 2\cdot\dfrac{3^6 - 1}{3 - 1} = 2\cdot\dfrac{728}{2} = 728

S6=728S_6 = 728. Check: 2+6+18+54+162+486=7282 + 6 + 18 + 54 + 162 + 486 = 728 ✓

Example 2 · Count the terms first

Find the sum 3+6+12+⋯+7683 + 6 + 12 + \cdots + 768.

  1. a1=3, r=2a_1 = 3,\ r = 2. The last term is 3⋅2n−1=768⇒2n−1=256=283\cdot 2^{n-1} = 768 \Rightarrow 2^{n-1} = 256 = 2^8, so there are n=9n = 9 terms

  2. S9=3⋅29−12−1=3(511)=1533S_9 = 3\cdot\dfrac{2^9 - 1}{2 - 1} = 3(511) = 1533

15331533. A common mistake is miscounting n; always find it from an=a1rn−1a_n = a_1r^{n-1}.

Infinite geometric series

When the sum never stops, look at what rnr^n in the formula for SnS_n does as n→∞n \to \infty. If ∣r∣<1|r| < 1, then rn→0r^n \to 0 and the sum approaches a finite value.

S∞=a1+a1r+a1r2+⋯=a11−r,∣r∣<1S_\infty = a_1 + a_1r + a_1r^2 + \cdots = \frac{a_1}{1 - r},\qquad |r| < 1
Value of rBehaviour of the infinite series
∣r∣<1|r| < 1Converges, with sum a1/(1−r)a_1/(1 - r)
r=1r = 1Diverges; the sum grows like na1na_1
r=−1r = -1Diverges; the partial sums oscillate a1,0,a1,0,…a_1, 0, a_1, 0, \dots
∣r∣>1|r| > 1Diverges; the terms grow without bound
Example 3 · Repeating decimals and negative r

(a) Write 0.36‾0.\overline{36} as a fraction. (b) Find 8−4+2−1+⋯8 - 4 + 2 - 1 + \cdots.

  1. (a) 0.3636…=0.36+0.0036+⋯0.3636\ldots = 0.36 + 0.0036 + \cdots with a1=0.36, r=0.01a_1 = 0.36,\ r = 0.01: 0.361−0.01=3699=411\dfrac{0.36}{1 - 0.01} = \dfrac{36}{99} = \dfrac{4}{11}

  2. (b) a1=8, r=−12a_1 = 8,\ r = -\tfrac12 and ∣r∣<1|r| < 1: S∞=81+12=163S_\infty = \dfrac{8}{1 + \frac12} = \dfrac{16}{3}

(a) 411\tfrac{4}{11} (b) 163\tfrac{16}{3}. By the same reasoning, 0.999…=0.91−0.1=10.999\ldots = \tfrac{0.9}{1 - 0.1} = 1 exactly.

Example 4 · A bouncing ball

A ball is dropped from a height of 10 m. Each time it hits the floor it bounces back to 60% of its previous height. Find the total distance travelled.

  1. The first fall is 10 m. After that, every bounce has equal up and down legs: 6+3.6+2.16+⋯6 + 3.6 + 2.16 + \cdots is a geometric series with a1=6, r=0.6a_1 = 6,\ r = 0.6

  2. Total distance =10+2⋅61−0.6=10+30=40 m= 10 + 2\cdot\dfrac{6}{1 - 0.6} = 10 + 30 = 40\ \text{m}

40 m40\ \text{m}: infinitely many bounces, but a finite total distance.

Engineering uses

  • Digital filter (EMA) y[n]=0.8 y[n−1]+0.2 x[n]y[n] = 0.8\,y[n-1] + 0.2\,x[n] with a unit step input gives y[n]=0.2(1+0.8+⋯+0.8n)=1−0.8n+1y[n] = 0.2(1 + 0.8 + \cdots + 0.8^n) = 1 - 0.8^{n+1}. It reaches 95% at the 14th sample and is stable because ∣0.8∣<1|0.8| < 1.
  • Present value Rooftop solar that saves 12,000 baht a year for 20 years at a 5% discount rate: PV=12000⋅1−1.05−200.05≈149,547PV = 12000\cdot\dfrac{1 - 1.05^{-20}}{0.05} \approx 149{,}547 baht.
  • Power series 11−x=1+x+x2+⋯\dfrac{1}{1 - x} = 1 + x + x^2 + \cdots (∣x∣<1|x| < 1) is the starting point for the series of ln⁡(1+x)\ln(1 + x) and arctan⁡x\arctan x in Taylor series.

Common mistakes

  • Using a1/(1−r)a_1/(1 - r) when ∣r∣≥1|r| \ge 1. For example, 1+2+4+⋯1 + 2 + 4 + \cdots does not equal 11−2=−1\tfrac{1}{1 - 2} = -1; it diverges.
  • Using the formula when r=1r = 1 (division by zero). In that case Sn=na1S_n = na_1.
  • Miscounting the number of terms, especially when the series starts at r0r^0 versus r1r^1.
  • Forgetting that rr can be negative: a sequence with alternating signs can still be geometric.

Keep learning in the library

The full lessons are in Thai, with English technical terms and the same formulas.

Frequently asked questions

When does an infinite geometric series converge?

Only when ∣r∣<1|r| < 1, and then its sum is a11−r\dfrac{a_1}{1 - r}. If ∣r∣≥1|r| \ge 1 the terms do not approach zero, so the series diverges.

Can I use the sum formula when r = 1?

No, because the denominator 1−r=01 - r = 0. In that case every term equals a1a_1, so the sum of n terms is simply na1n a_1.

What is the difference between a geometric sequence and a geometric series?

A geometric sequence is the list of numbers a1,a1r,a1r2,…a_1, a_1r, a_1r^2, \dots; a geometric series is their sum a1+a1r+a1r2+⋯a_1 + a_1r + a_1r^2 + \cdots.

Where are geometric series used in engineering?

In the response of digital filters, the present value of projects such as rooftop solar, total distances in repeated reflections, and as the starting point of the power series 11−x=1+x+x2+⋯\frac{1}{1 - x} = 1 + x + x^2 + \cdots used to build Taylor series.

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