Geometric Series: Formula, Examples and How to Find the Sum
A geometric series adds numbers that are multiplied by the same factor each time, such as 2+6+18+54. There is one formula to remember and one condition to check when the sum goes on forever. This article covers the formula, where it comes from, and the examples that appear most often in exams.
General term: an=a1rn−1, where r is the common ratio =an+1/an
Sum of n terms: Sn=a11−r1−rn for r=1
Infinite series: S∞=1−ra1, valid only when ∣r∣<1
What is a geometric series?
A geometric sequence is a sequence in which each term is the previous one multiplied by a constant r, for example 2,6,18,54,… with r=3. A geometric series is the sum of those terms, 2+6+18+54+⋯.
To find r, divide any term by the one before it. If every pair gives the same value, the sequence is geometric. r can be negative (the signs alternate) or a fraction (the terms shrink).
Sum of n terms, and where the formula comes from
Sn=a1+a1r+a1r2+⋯+a1rn−1=a11−r1−rn,r=1
The derivation takes two lines: write Sn, then multiply by r. You get the same terms shifted by one place.
Subtract: all the middle terms cancel, leaving Sn−rSn=a1−a1rn, which gives the formula above. When r>1 you can write it as a1r−1rn−1 instead (same value, fewer minus signs).
Example 1
A geometric sequence has a2=6 and a5=162. Find S6.
a2a5=r3=6162=27, so r=3 and a1=a2/r=2
S6=2⋅3−136−1=2⋅2728=728
S6=728. Check: 2+6+18+54+162+486=728 ✓
Example 2 · Count the terms first
Find the sum 3+6+12+⋯+768.
a1=3,r=2. The last term is 3⋅2n−1=768⇒2n−1=256=28, so there are n=9 terms
S9=3⋅2−129−1=3(511)=1533
1533. A common mistake is miscounting n; always find it from an=a1rn−1.
Infinite geometric series
When the sum never stops, look at what rn in the formula for Sn does as n→∞. If ∣r∣<1, then rn→0 and the sum approaches a finite value.
S∞=a1+a1r+a1r2+⋯=1−ra1,∣r∣<1
Value of r
Behaviour of the infinite series
∣r∣<1
Converges, with sum a1/(1−r)
r=1
Diverges; the sum grows like na1
r=−1
Diverges; the partial sums oscillate a1,0,a1,0,…
∣r∣>1
Diverges; the terms grow without bound
Example 3 · Repeating decimals and negative r
(a) Write 0.36 as a fraction. (b) Find 8−4+2−1+⋯.
(a) 0.3636…=0.36+0.0036+⋯ with a1=0.36,r=0.01: 1−0.010.36=9936=114
(b) a1=8,r=−21 and ∣r∣<1: S∞=1+218=316
(a) 114 (b) 316. By the same reasoning, 0.999…=1−0.10.9=1 exactly.
Example 4 · A bouncing ball
A ball is dropped from a height of 10 m. Each time it hits the floor it bounces back to 60% of its previous height. Find the total distance travelled.
The first fall is 10 m. After that, every bounce has equal up and down legs: 6+3.6+2.16+⋯ is a geometric series with a1=6,r=0.6
Total distance =10+2⋅1−0.66=10+30=40m
40m: infinitely many bounces, but a finite total distance.
Engineering uses
Digital filter (EMA)y[n]=0.8y[n−1]+0.2x[n] with a unit step input gives y[n]=0.2(1+0.8+⋯+0.8n)=1−0.8n+1. It reaches 95% at the 14th sample and is stable because ∣0.8∣<1.
Present value Rooftop solar that saves 12,000 baht a year for 20 years at a 5% discount rate: PV=12000⋅0.051−1.05−20≈149,547 baht.
Power series1−x1=1+x+x2+⋯ (∣x∣<1) is the starting point for the series of ln(1+x) and arctanx in Taylor series.
Common mistakes
Using a1/(1−r) when ∣r∣≥1. For example, 1+2+4+⋯ does not equal 1−21=−1; it diverges.
Using the formula when r=1 (division by zero). In that case Sn=na1.
Miscounting the number of terms, especially when the series starts at r0 versus r1.
Forgetting that r can be negative: a sequence with alternating signs can still be geometric.
Keep learning in the library
The full lessons are in Thai, with English technical terms and the same formulas.
Only when ∣r∣<1, and then its sum is 1−ra1. If ∣r∣≥1 the terms do not approach zero, so the series diverges.
Can I use the sum formula when r = 1?
No, because the denominator 1−r=0. In that case every term equals a1, so the sum of n terms is simply na1.
What is the difference between a geometric sequence and a geometric series?
A geometric sequence is the list of numbers a1,a1r,a1r2,…; a geometric series is their sum a1+a1r+a1r2+⋯.
Where are geometric series used in engineering?
In the response of digital filters, the present value of projects such as rooftop solar, total distances in repeated reflections, and as the starting point of the power series 1−x1=1+x+x2+⋯ used to build Taylor series.